- P147's solution
-
题解P147
- @ 2025-11-12 15:38:23
按题意直接模拟即可。
AC code:
#include <bits/stdc++.h>
using namespace std;
typedef pair<int, int> pii;
int main() {
int n, k;
cin >> n >> k;
vector<pii> in(n);
for (int i = 0; i < n; i++) {
cin >> in[i].first >> in[i].second;
}
if (n == 0) {
cout << 1 << " " << k << endl;
return 0;
}
sort(in.begin(), in.end());
vector<pii> m;
m.push_back(in[0]);
for (int i = 1; i < n; i++) {
pii& last = m.back();
if (in[i].first <= last.second) {
last.second = max(last.second, in[i].second);
} else {
m.push_back(in[i]);
}
}
int prev = 1;
for (const auto& in : m) {
int l = in.first;
int r = in.second;
if (prev <= l - 1) {
cout << prev << " " << l - 1 << endl;
}
prev = r + 1;
if (prev > k) {
break;
}
}
if (prev <= k) {
cout << prev << " " << k << endl;
}
return 0;
}