参考资料：

http://www.360doc.com/content/24/0621/17/8797307_1126794154.shtml

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int x, y, z;
    cin >> x >> y;
    z = x * y;
    if (z & 1) printf("1 %lld 1 %lld\n", (1ll * z * z - 1) / 2, (1ll * z * z + 1) / 2);
    else printf("1 %lld 1 %lld\n", 1ll * z * z / 4 - 1, 1ll * z * z / 4 + 1);
    return 0;
}